given log base 10 2 = 0.30 10 and log base 10 3 = 0.477 1 if 5^x-1 = 6^2-x then the value of x is ?
Answers
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Step-by-step explanation:
We can write it as:
log
10
(
15
)
=
log
10
(
30
2
)
using the property of logs of a fraction we get:
log
10
(
30
2
)
=
log
10
(
30
)
−
log
10
(
2
)
=
and:
=
log
10
(
10
⋅
3
)
−
log
10
(
2
)
=
we use the property of the log of a product to get:
log
10
(
10
)
+
log
10
(
3
)
−
log
10
(
2
)
=
=
1
+
0.477
−
0.301
=
1.176
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