given sign A=3/5 find tanA and cosA
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★ TRIGONOMETRIC REDUCTIONS ★
SinA = 3/5 = P/H
Hence , B [ base ] = 4
TanA = P/B = 3/4
And
CosA = B/H = 4/5
Consider the general standard right angled triangle for the above results
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SinA = 3/5 = P/H
Hence , B [ base ] = 4
TanA = P/B = 3/4
And
CosA = B/H = 4/5
Consider the general standard right angled triangle for the above results
★✩★✩★✩★✩★✩★✩★✩★✩★✩★
siddhartharao77:
Nice Explanation Bro
Thanks ^_^
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this is the answer of the above question.......
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