Given sino = 12/13 caluclate coso and tano
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Question:-
➡ If sin(x) = 12/13, calculate cos(x) and tan(x)
Solution:-
Given that,
➡ sin(x) = 12/13
➡ sin²(x) = (12/13)²
➡ sin²(x) =144/169
We know that,
sin²(x) + cos²(x) = 1
Substituting sin²(x), we get,
➡ 144/169 + cos²(x) = 1
➡ cos²(x) = 1 - 144/169
➡ cos²(x) = (169 - 144)/169
➡ cos²(x) = 25/169
➡ cos(x) = √(25/169)
➡ cos(x) = 5/13 (omitting negative sign)
Now, tan(x) = sin(x)/cos(x)
➡ tan(x) = 12/13 ÷ 5/13
➡ tan(x) = 12/13 × 13/5
➡ tan(x) = 12/5
Hence,
➡ cos(x) = 5/13
➡ tan(x) = 12/5
Answer:-
➡ cos(x) = 5/13
➡ tan(x) = 12/12
Formula Used:-
➡ sin²(x) + cos²(x) = 1
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hey hope above answer helps u .
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