Question

given that √5 is irrational prove the 2√5-3 is a irrational number​

Answer 1

Answer:

Let us assume to the contrary that 2√5 − 3 is a rational number∴ 2√5 − 3 = p/q   where p and q are integers and q ≠ 0⇒ √5 = p+3q/2q... 1Since p and q are integers∴ p +3a/2q is a rational number∴ √5 is a rational number which is a contradiction as √5 is an irrational number. Hence our assumption is wrong and hence 2√5 − 3 is an irrational number.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$\sqrt[5]{25}$