Question

given that 8x² – 2xy – 3y² = 0; then y in term of x is:
(a) 4x/3 and 2x
(b) 4x/3 and –2x
(c) –4x/3 and –2x
(d) 4/3x and –2x
please give explanation.​

Answer 1

Answer:

8x² - 6xy + 4xy - 3y² <-------- Now group the terms! Easy right?

2x(4x - 3y) + y(4x - 3y)

(2x + y)(4x - 3y)

Step-by-step explanation:

8x² - 3y² - 2xy= 0

-3y²= 2xy -8x²

y²= 2xy-8x²/-3

pls mark brainliest

Answer 2

Answer:

Your answer is... (b) 4x/3 and -2x

Step-by-step explanation:

8x² - 2xy - 3y² = 0

=> 8x² - 6xy + 4xy - 3y² = 0

=> 2x (4x - 3y) + y (4x - 3y) = 0

=> (4x - 3y)(2x + y) = 0

if, 4x - 3y = 0

=> y = 4x/3

or, 2x + y = 0

=> y = -2x

Hope it will help you.

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