Question

chapter 8 comparing quantities
1.find the amount and the compound interest on Rs.5000 for 2 1/2 yearsat 8% per annum compounded annually

Answer 1

Answer:

$Amount =>Rs.6065.28 </p><p>C.I. \: =>Rs.1065.28$

Step-by-step Explanation:

$For \: the \: first \: year: \\ Principal (P) =Rs.5000, \\ Rate \: of \: interest (R)= 8 \% \: and \\ Time (T)=1 \: year \\ ∴I=Rs. \frac{5000 \times 8 \times 1}{100} = Rs.400 \\ and \: amount \: at \: the \: end \: of \: first \: \\ year,A=P+I = Rs.(5000 + 400) \\ = Rs.5400 \\ \\ For \: the \: second \: year: \\ Principal (P) =Rs.5400, \\ Rate \: of \: interest (R)= 8 \% \: and \\ Time (T)=1 \: year \\ ∴I=Rs. \frac{5400 \times 8 \times 1}{100} = Rs.432 \\ and \: amount \: at \: the \: end \: of \: second \: \\ year,A=P+I=Rs.(5400+432) \\ =Rs.5832 \\ \\ For \: the \: last \: \frac{1}{2} \: year: \\ Principal (P) =Rs.5832, \\ Rate \: of \: interest (R)= 8 \% \: and \\ Time (T)= \frac{1}{2} \: year \\ ∴I=Rs. \frac{5832 \times 8 \times 1}{100 \times 2} = Rs.233.28 \\ and \: amount \: at \: last,A=P+I \\ =Rs.(5832+233.28) \\ = > Rs.6065.28 \\ Since, \: the \: amount \: in \: 2 \frac{1}{2} \: years \\ is \: Rs.6065.28 \: and \: the \: original \: \\ principal \: is \: Rs.5000. \\ ∴C.I. = Rs.6065.28 - Rs.5000 \\ = > Rs.1065.28$

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