Given that a,b,c and d are natural numbers and that a=bcd, b=cda, d=abc then (a+b+c+d)^2
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Answered by
7
Hi ...dear...here Is your!!
let's start!!
.
given....
a=bcd (1)
b=cda (2)
c=dab (3)
d=abc (4)
On dividing equation 1 by 2 ,
a/b = bcd/cda
a/b = b/a
a2 = b2
On taking squreroot of both sides
a = b...
.. similarly when we divide equation 2 by 3 ..
we get b=ç.
and so on ..
a=b=c=b......
.
see.picture!!!
Hope it helped you!!
Regards Brainly Star Community.
#shubhendu
let's start!!
.
given....
a=bcd (1)
b=cda (2)
c=dab (3)
d=abc (4)
On dividing equation 1 by 2 ,
a/b = bcd/cda
a/b = b/a
a2 = b2
On taking squreroot of both sides
a = b...
.. similarly when we divide equation 2 by 3 ..
we get b=ç.
and so on ..
a=b=c=b......
.
see.picture!!!
Hope it helped you!!
Regards Brainly Star Community.
#shubhendu
Attachments:
Shubhendu8898:
what happens after cd=1
After cd=1
We also have c=d
So from cd=1, we can write c^2 = 1
So, c = 1 or c = -1
So, a=b=c=d = 1 OR a=b=c=d = -1
But finally answer remains 16
now i got it!!!thanks a lot!!!i was just little bit comfuse!!
thanks for giving me a chance to edit it
Thanks for editing it :)
Answered by
0
Answer:
given....
a=bcd (1)
b=cda (2)
c=dab (3)
d=abc (4)
On dividing equation 1 by 2 ,
a/b = bcd/cda
a/b = b/a
a2 = b2
On taking squreroot of both sides
a = b...
.. similarly when we divide equation 2 by 3 ..
we get b=ç.
and so on ..
a=b=c=b......
.
Step-by-step explanation:
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