Given that HCF (336,54) is 6, find LCM
The diameter of a wheel is 1.54 m. How
Express 234 as the product of primes
Find the area of a quadrant of a circle
A pair of linear equations of two van
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Step-by-step explanation:
HCF × LCM = a × b
given a = 336 and b = 54 and HCF = 6
therefore LCM = (a×b)/HCF
=> LCM = (336 × 54)/6
=> LCM = 3024
Area of quadrant of a circle = πr²×90/360
=> πr²/4
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