Math, asked by yaint, 6 months ago

Given that K is real, find the set of values of K for which the roots of (1+2K)x^2-10x+(K-2)=0 have a sum which is greater than 1.

The answer is -1/2 < K < 1/2 but I don't know the method.
I would appreciate any help. ​

Answers

Answered by lalankumar99395
4

Step-by-step explanation:

Given that K is real, find the set of values of K for which the roots of (1+2K)x^2-10x+(K-2)=0 have a sum which is greater than 1.

The answer is -1/2 < K < 1/2 but I don't know the method.

I would appreciate any help

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Answered by beautyblgger12345
0

Step-by-step explanation:

Given that K is real, find the set of values of K for which the roots of (1+2K)x^2-10x+(K-2)=0 have a sum which is greater than 1.

The answer is -1/2 < K < 1/2 but I don't know the method.

I would appreciate any help.

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