Question

Given that root3=1.732,find the value of the root 75+1/2root48-root 192

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{ \sqrt{75} + 1}{2 \sqrt{48} - \sqrt{192} } \\ \\ \frac{ \sqrt{5 \times 5 \times 3} + 1}{ \sqrt{2 \times 2 \times 2 \times 2 \times 3} - \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3} } \\ \\ = \frac{5 \sqrt{3} + 1}{2 \times 2 \sqrt{3} - 2 \times 2 \times 2 \sqrt{3} } \\ \\ = \frac{5 \sqrt{3} + 1}{4 \sqrt{3} - 8 \sqrt{3} } \\ \\ = \frac{5 \sqrt{3} + 1}{ - 4 \sqrt{3} } \\ \\ on \: rationalizing \: the \: denominator \: we \: get \\ \\ = \frac{ - 5 \sqrt{3} - 1}{4 \sqrt{3} } \times \frac{4 \sqrt{3} }{4 \sqrt{3} } \\ \\ = \frac{ - 5 \sqrt{3} \times 4 \sqrt{3} - 1 \times 4 \sqrt{3} }{ {(4 \sqrt{3} )}^{2} } \\ \\ = \frac{ - 60 - 4 \sqrt{3} }{48} \\ \\ = \frac{ - 15 - \sqrt{3} }{12} \\ \\ = \frac{ - 15 - 1.732}{12} \\ \\ = \frac{ - 16.732}{12} \\ \\ = \frac{ - 4.183}{3}$

Hope this helps!!!

@Mahak24

Thanks...
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