Question

given that sin theta =a/b ,then cos theta =​

Answer 1

Answer:

$\frac{\sqrt{(a^{2}+b^{2} )} }{b\\}$

Step-by-step explanation:

Sin Theta= Perpendicular/Hypotenuse= a/b

Taking k as the constant term, Perpendicular= a.k

                                                    Hypotenuse= b.k

∴Base= $\sqrt{(a^{2}k^{2} +b^{2}k^{2} ) } = \sqrt{(a^{2}+b^{2})k^{2} } =\sqrt{(a^{2}+b^{2})}k$ ( by Pythogorus Theorum

Cos Theta= Base/Hypotenuse= $\frac{ \sqrt{(a^{2}+b^{2}) } k}{bk}$

                                                  =$\frac{\sqrt{(a^{2}+b^{2} )} }{b\\}$