Question

The ratio of velocity of the electron of H atom in two of the first six orbits n, and n, is 1:3. The difference
between potential energy of electron in the two orbits n, and n, i.e. (PE, -PE) can be -
(A) Either -12.09 eVor-3.02 eV
(B) Either 24.18 eV or 6.04 eV
(C) Either 12.09 eV or 3.02 eV
(D) Either -24.18 eV or -6.04 eV​

Answer 1

Answer:

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Explanation:

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