Question

Given three points p q r with p(5 3) and r lies on the x axis

Answer 1

Centroid  =  ( 5 , 2) lies on  2x−5y=0     if  three points p q r with p(5 3) and r lies on the x axis  equation of RQ is x-2y=2 and PQ is parallel to x-axis

Step-by-step explanation:

Complete Question

if equation of RQ is x-2y=2 and PQ is parallel to x-axis then find the centroid of triangle PQR lies on

(a)2x+y−9=0(b)x−2y+1=0(c)5x−2y=0(d)2x−5y=0

RQ  

x - 2y = 2

R lies on x axis  => y = 0

=> x - 0 = 2

=> x = 2

=> R = ( 2, 0)

PQ ║ x axis

P = ( 5, 3)

=> Q   y coordinate = 3

x - 2 * 3 = 2

=> x = 8

Q = ( 8,3)

P =  (5 , 3)  ,

Q = (8 , 3)

R = ( 2 , 0)

Centroid  =  ( 5 + 8 + 2)/3  , (3 + 3 + 0)/3

= ( 5 , 2)

lies on  2x−5y=0  

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