Question

Given triangle abc congruent triangle pqr of AB/PQ=1/3 then find ar Triangle abc/ triangle pqr

Answer 1

Solution :-

Given that Δ ABC ~ Δ PQR

And, 

AB/PQ = 1/3

We know that the ratio of two similar triangles is equal to the ratio of the squares of their corresponding sides.

So, 

Area of triangle ABC/Area of triangle PQR = (AB)²/(PQ)²

⇒ (1)²/(3)²

⇒ 1/9 

So, Area of triangle ABC/Area of triangle PQR is 1/9

Answer.

Answer 2

Thank you for asking this question. Here is your answer:

We will use the theorem on similar triangles.

The area of the two triangles will be in a ratio of the squares of their corresponding sides.

Now we will let the unknown constant  of proportionality be x.

Now we will solve it:

Area of ΔABC/ Area of ΔPQR = AB²/PQ² ⇒ (1x)²/(3x)² ⇒ x²/9x²

Area of ΔABC : Area of ΔPQR = 1 : 9

So the final answer is 1:9

If there is any confusion please leave a comment below.