given triangle ABC is similar to triangle pqr if a b upon PQ equal to 1 by 3 then find area of triangle ABC upon Triangle pqr
Answers
Answered by
13
Solution :-
Given that the Δ ABC is similar to the Δ PQR
And,
AB/PQ = 1/3
We know that the ratio of two similar triangles is always equal to the ratio of the squares of their corresponding sides.
So,
Area of ΔABC/Area of Δ PQR = (AB/)²(PQ)²
⇒ (1)²/(3)²
⇒ 1/9
So, Area of Δ ABC/Area of Δ PQR = 1/9
Answer.
Given that the Δ ABC is similar to the Δ PQR
And,
AB/PQ = 1/3
We know that the ratio of two similar triangles is always equal to the ratio of the squares of their corresponding sides.
So,
Area of ΔABC/Area of Δ PQR = (AB/)²(PQ)²
⇒ (1)²/(3)²
⇒ 1/9
So, Area of Δ ABC/Area of Δ PQR = 1/9
Answer.
Golda:
it is (AB)^2/(PQ)^2
Answered by
6
GIVEN:
ΔABC ~ Δ PQR & AB/PQ = 1/3
ar(ΔABC)/ar( Δ PQR )= AB²/ PQ²
[The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.]
ar(ΔABC)/ar( Δ PQR ) = 1²/3²
[Given =AB/PQ = ⅓]
ar(ΔABC)/ar( Δ PQR ) = 1/9
Hence, the Area of ΔABC/Area of ΔPQR = 1/9
HOPE THIS WILL HELP YOU….
ΔABC ~ Δ PQR & AB/PQ = 1/3
ar(ΔABC)/ar( Δ PQR )= AB²/ PQ²
[The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.]
ar(ΔABC)/ar( Δ PQR ) = 1²/3²
[Given =AB/PQ = ⅓]
ar(ΔABC)/ar( Δ PQR ) = 1/9
Hence, the Area of ΔABC/Area of ΔPQR = 1/9
HOPE THIS WILL HELP YOU….
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