Question

Good morning

For the straight line 4x + 3y - 6 and 5x + 12y + 9 = 0 find the equation of the -

(1) bisector of obtuse angle between them

(2) Bisector of acute angle between them

(3) Bisector of the angle which contains origin.

(4) Bisector of the angle which contains (1,2) .

Answer 1

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4x+3y-6/√4^2+3^2=

5x+12y+9/√5^2+12^2

=] 4x+3y-6 / 5 =

5x-12y+9/13

=]52x+39y-78= +-

(25x+60y+45)

=]0=0

=]8x-7y-41=0

7x-9y-3=0

=]tane= | -4/3 -9/7/(-4/3 )

9/7 |

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