Question

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Plz Solve it

Find radius of 2 orbit of hidrogan Atom

Answer 1

What is the value of Bohr’s radius of the second orbit of hydrogen?

Ok according to this question

There is a formula in chemistry regarding the Bohr's radius of hydrogen atom

r = r°n×n÷z

In this formula R is the radius and n is the radius in which the electron is lying

Z is the atomic number of the atom in the case of hydrogen atom Z is equal to one

r°=0.529

Therefore for Bohr's radius of second Orbit n is equal to 2

r= 0.529 × 2×2

r=2.116

Remember this value comes in A°

Therefore radius of second orbit is 2.116

I hope this will be helpful to you

Answer 2

$<b>$Question-:How can you calculate the radius of the first orbit in a hydrogen atom?

ke2/r2 = mv2/r


Where ke2/r2 is the Coulomb's force and mv2/r is the centripetal force of the electron around the nucleus

you know from Bohr's postulate

mvr = nh/2π

 

Combine the two equations. What is the value of the radius of the first orbit ?

 

r=

Plank's constant h= 6.624 10-34 Js

electron mass me= 9.11 10-31 Kg

electron charge e= -1.6 10-19 C

Coulomb's constant k=8.99 109 m2N/C2

 
$<b>$Answrr

ke2/r2 = mv2/r

3rd Bohr's postulate

mvr = nh/2Π

 

v = nh/2Πmr

ke2/r2 = mn2h2/r4Πm2r2

 

r = n2h2/k4Π2me2

 

r = 0.53 Angstrom