Question

Greg has an MP3 player called the Jumble. The Jumble randomly selects a song for the user to listen to. Greg's Jumble has 666 classical songs, 777 rock songs, and 999 rap songs on it.
What is \text{P(not a rap song})P(not a rap song)start text, P, left parenthesis, n, o, t, space, a, space, r, a, p, space, s, o, n, g, end text, right parenthesis?
If necessary, round your answer to 222 decimal places.

Answer 1

Step-by-step explanation:

Number of classical songs = 6

Number of rock songs = 7

Number of rap songs = 9

Total number of songs = 6 + 7 + 9 = 22

Number of not rap songs = Number of classical songs + Number of rock songs

Number of not rap songs = 6 + 7 = 13

P(not a rap song) =

P(not a rap song) =

P(not a rap song) = 0.5909

P(not a rap song) = 0.59

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Answer 2

The value of P( not a rap song ) $=\dfrac{13}{22}$ .

Explanation:

Given : The number of classical songs =6

The number of rock songs =7

The number of rap songs =9

Total songs = 6+7+9=22

Now , the probability that the selected songs is a rap song :

P(a rap song) =$\dfrac{\text{Number of rap songs}}{\text{Total songs}}$

i.e. P(a rap song)$=\dfrac{9}{22}$

Then, P( not a rap song ) = 1- P(a rap song)

= $1-\dfrac{9}{22}=\dfrac{22-9}{22}=\dfrac{13}{22}$

Hence, the value of P( not a rap song ) $=\dfrac{13}{22}$ .

# Learn more :

If a two digit number is chosen at random than find the probability that the number chosen is are multiple of three

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