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If triangle ABC is right angled at C, then the value of cos (A+B) is
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Answered by
1
Hey !!
Good morning , have a nice day you too ☺
HERE IS UR SOLUTION
A + B + C = 180°
A + B = 180° - C
Cos(A + B) = cos ( 180° - C)
Cos(A + B ) = cos ( 180° -90°)
Cos ( A + B ) = cos90°
Cos(A + B ) = 0 Answere
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Hope it helps you !!!
@Rajukumar111
Good morning , have a nice day you too ☺
HERE IS UR SOLUTION
A + B + C = 180°
A + B = 180° - C
Cos(A + B) = cos ( 180° - C)
Cos(A + B ) = cos ( 180° -90°)
Cos ( A + B ) = cos90°
Cos(A + B ) = 0 Answere
**************************
Hope it helps you !!!
@Rajukumar111
Answered by
2
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A + B + C = 180°
A + B = 180° - C
Cos(A + B) = cos ( 180° - C)
Cos(A + B ) = cos ( 180° -90°)
Cos ( A + B ) = cos90°
Cos(A + B ) = 0
Therfore, O is the answer
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