Question

Gud nyt frnds
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so the question is
$find \: (4 - \frac{1}{n} ) + (7 - \frac{2}{n} ) + (10 - \frac{3}{n} ) + ....... \: upto \: n \: terms$

Answer 1

4+7+10-(1/n+2/n+3/n)=>21-6/n .Hope it helps you. Please mark me as Brainliest.

Answer 2

Given,
AP:- (4-1/n), (7-2/n), (10-3/n)..........
Here,
T¹= 4-1/n, T²= 7-2/n
d= 7-2/n - (4-1/n)
= 7-4-2/n+1/n
= 3-1/n
Now,
Tn= a+(n-1)d
= 4-1/n+(n-1)(3-1/n)
= 4-1/n+3n-3-1+1/n
= 4+3n-4 [+1/n & -1/n cancel out]
Tn= 3n

Hope this helps you!