Math, asked by anna5264, 1 year ago

guys answer me

ita urgent so answer me quick ​

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anna5264: cos theta =4/21 then what is the value of theta
anna5264: ohh thanks actually i did like same but last line
sswaraj04: 79 degrees
sswaraj04: is it correct??
anna5264: i donot know
sswaraj04: ohk

Answers

Answered by sswaraj04
4

Answer:

Step-by-step explanation:

a=2i + 2j - k

b=6i - 3j +2k

|a| =root(2^2 + 2^2 + 1^2)

   =root(9)=3

|b|=root(6^2 + 3^2 + 2^2)

   =root(49) = 7

a . b = |a| |b| cos @                       where @ is angle btw vectors

a . b = (2i + 2j - k) . (6i - 3j +2k)

       =12 - 6 -2

       =4

cos@ = a . b / (|a| |b|)

cos @ = 4/(7*3)=4/21

@= cos^-1(4/21)

Hope it's correct and helps you


anna5264: thanks a lot
anna5264: i have other some question from this chapter will u help me ?
mohamed28: ok
mohamed28: i will help you
anna5264: thanks
mohamed28: ok
biprajitsuklabaidya7: anna here
Answered by Niteshyadav916640
2

Answer:

your solution is in image

Attachments:

Niteshyadav916640: Have you understood or not ?
anna5264: hm
mohamed28: ok
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