Question

rationalise the denomination of [6-3√2/6+3√2]​

Answer 1

Answer:

answer is 3 -2√2

Step-by-step explanation:

[(6 - 3√2)/(6 + 3√2)]

= [(6-3√2)/(6+3√2)] × [(6-3√2)/(6-3√2)]

= (6 - 3√2)² / [(6)² - 3√2)²]

= ( 36 + 18 - 36√2) / [36 - 18]

= ( 54 - 36√2) / 18

= 18(3 - 2√2) / 18

= 3 - 2√2

Answer 2

Answer:

The rationalised value is

(6-3√2)/(6+3√2) = (3-2√2)

Step-by-step explanation:

(6-3√2)/(6+3√2)

To rationalize, we multiply (6-3√2) in both numerator and denominator and solving it :-

=(6-3√2)²/(6+3√2)(6-3√2)

={6²+(3√2)²-2.6.3√2 }/6²-(3√2)²

=(36+18-36√2)/36-18

=(54 -36√2)/18

Taking 2 as common from both numerator and denominator and cancelling them:-

=(27-18√2)/9

Again taking 3 as common from both numerator and denominator and cancelling them:-

=(9-6√2)/3

Again taking 3 as common from both numerator and denominator and cancelling them:-

=(3-2√2)/1

The final answer is:-

=(3-2√2)