Question

guys plz help me to solve this question
plz answer fast ​

Answer 1

Answer:

first of all refer to the attachment

then . after that following steps

= 3√256

= 3*16

= 48 cm²

Answer 2

Answer:

Δ ABC

AB = AC = x

BC = 12 cm

Perimeter Δ ABC = 32

x + x + 12 = 32

2x = 32 - 12

x = $\frac{20}{2}$

x = 10 cm

AB = AC = 10 cm

Construct an altitude AD from A to side BC

In Δ ADB,

$AD = \sqrt{AD^{2} - BD^{2} }$        (an altitude bisects the base of an isoceles triangle)                                

       = $\sqrt{100 - 36}$

$= \sqrt{64\\} \\AD = 8 cm$

Area = $\frac{1}{2}$ × Base × Height

Area = $\frac{1}{2}$ × BC × AD                              

        = $\frac{1}{2}$ × 12 × 8

        = 6 × 8

        = 48 cm²