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Answer 1

height of object , h₀ = 4cm

object distance from centre of lens, u = 30cm

focal length , f = 20cm

Now, use lens formula,

1/v - 1/u = 1/f

Here, u = -30cm , f = 20cm

⇒1/v - 1/-30cm = 1/20cm

⇒ 1/v = 1/20 - 1/30 = (30-20)/20 × 30 = 1/60

v = 60cm

Hence, image is formed at 60cm right side of lens

Now, we should use magnification concept

m = v/u = height of image/height of object

60cm/-30cm = h/h₀ = h/4cm

⇒ -2 = h/4cm, h = -8cm, here negative sign shows that image is forming below the optical axis.

Now, ratio of image size/object size = 8cm/4cm {excluding sign} = 2

Answer 2

Answer:

Ratio of image size/ object size = 8cm/4cm = 2

Magnification= 2