guys solve this question its urgent !!!
calculate the mole fraction of sodium hydrogen carbonate in which 40% h2so4 contain by masds.
Answers
The first thing to do here is pick a sample of this solution.
Since you're going to find its molarity, you can make the calculations easier by picking a
1.00-L
sample. Keep in mind ,the answer will be the same regardless of the volume you pick.
So, use the density of the solution to determine how many grams you get in that respective volume
1.00
L
⋅
1000
mL
1
L
⋅
1.20 g
1
mL
=
1200 g
Now, you that the percent concentration by mass for this solution is
40.0% HCl
. This means that you get
40.0 g
of hydrochloric acid for every
100.0 g
of solution.
The mass of hydrochloric acid you get in that sample will thus be
1200
g solution
⋅
40.0 g HCl
100
g solution
=
480 g HCl
Use hydrochloric acid's molar mass to determine how many moles you have in that many grams
480
g
⋅
1 mole HCl
36.46
g
=
13.17 moles HCl
The molarity of the solution will thus be - remember that we started with a
1.00-L
sample
c
=
n
V
c
=
13.17 moles
1.00 L
=
13.2 M
→
rounded to three sig figs
SIDE NOTE This is very close to the maximum possible concentration for hydrochloric acid in aqueous solution. At this concentration, the solution is actually fuming at a significant evaporation rate.