H C F of 65 and 117 is expressible in the form 65n - 117 then find the value of n
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Step-by-step explanation:
find the HCF of 65 and 117,
117 = 1×65 + 52
65 = 1× 52 + 13
52 = 4 ×13 + 0
∴ HCF of 65 and 117 is 13.
65n - 117 = 13
65n = 117+13 = 130
∴n =130/65 = 2
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