Math, asked by abdullahzaki2003, 1 year ago

H C F of 65 and 117 is expressible in the form 65n - 117 then find the value of n ​

Answers

Answered by Anonymous
135

Answer:

Step-by-step explanation:

find the HCF of 65 and 117,

117 = 1×65 + 52

65 = 1× 52 + 13

52 = 4 ×13 + 0

∴ HCF of 65 and 117 is 13.

65n - 117 = 13

65n = 117+13 = 130

∴n =130/65 = 2


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Answered by girl12313
36

Answer:

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