h(t)=[t-1/t] differentiate
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Answer:
1+1/t^2
Step-by-step explanation:
t-1/t= t^1-t^(-1)
Here d/dt(t^n)=n×t^(n-1)
d/dt(t^1-t^(-1))=1×t^0-(-1)×t^(-2)
Therefore is equal to 1+1/t^2
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