Math, asked by ben1014, 11 months ago

h(t)=[t-1/t] differentiate​

Answers

Answered by adoohema
1

Answer:

1+1/t^2

Step-by-step explanation:

t-1/t= t^1-t^(-1)

Here d/dt(t^n)=n×t^(n-1)

d/dt(t^1-t^(-1))=1×t^0-(-1)×t^(-2)

Therefore is equal to 1+1/t^2

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