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The answer is given below :
Now,
(x + 1)/3 - (x + 7)/2 = 1
The lcm of 3 and 2 is = 3 × 2 = 6
So, we have
{2(x + 1) - 3(x + 7)}/6 = 1
=> 2x + 2 - 3x - 21 = 6
=> (2x - 3x) + (2 - 21) = 6
=> (-x) + (-19) = 6
=> -x = 6 + 19
=> x = - 25
So, the required solution be x = - 25
Thank you for your question.
Now,
(x + 1)/3 - (x + 7)/2 = 1
The lcm of 3 and 2 is = 3 × 2 = 6
So, we have
{2(x + 1) - 3(x + 7)}/6 = 1
=> 2x + 2 - 3x - 21 = 6
=> (2x - 3x) + (2 - 21) = 6
=> (-x) + (-19) = 6
=> -x = 6 + 19
=> x = - 25
So, the required solution be x = - 25
Thank you for your question.
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