Question

Three number are in AP.There sum is 48 and product of 1st and 3rd term is175 .find the number

Answer 1

let terms are a , a-d,a+d
:.a+a+a-d+a+d=48
3a=48
a=16
(a-d)(a+d)=175
a^2-d^2=175
256-d^2=175
d^2=81
d=9
:. nos are 16,25,7

Answer 2

Hey

Here is your answer,

Let the three numbers be a+d,a,a-d.

A+d+a+a-d=48
3a=48
A=48/3
A=16

(A+d)(a-d) = 175
A^2 - d^2 =175
(16)^2 - d^2 = 175
-d^2 =175 - 256
=-81
D=+/-9

If d = +9
A+d =25
A=16
A-d=7

If d=-9
A-d=25
A=16
A+d=7

Hope it helps you!