Question

Half life period of a radioactive substance is 20 days .After 30 days what percentage of the substance will be left?

This is the questions of class 12 Chemistry - Kinetics
Please answer using the chemistry formula

Experts ....please answer and make sure the spam comments have their points removed...Thanks

Answer 1

Answer:

0.87

Explanation:

Here half life is 20 days, so L=ln(2)/20.

The time elapsed here is 30 days so Lt=[ln(2)/20]x30 or ln(6)/2.

Thus after 30 days, N/No=exp[-ln(6)/2]=exp(- 0.778/2)=exp(-0.389)= 0.67773427 = 0.87

This is the proportion of atoms of radioactive substance left after 30 days

Answer 2

Answer:

Explanation: Refer to the attachment given