Question

Half of perimeter of a rectangular garden is 36m .If length 4m more than its breadth find ots dimensions in two variables

Answer 1

thats the solution of it

Answer 2

$\mathbb{\pink{\huge{Hello\:Mate!!!}}}$

$<b><u>Answer</u></b>$

Length is 20m and breadth is 16m.

$<b><u>Step-by-step explanation</u></b>$

Given that,

Half perimeter = $36m$

Therefore, total perimeter = $36m × 2$

Total perimeter = $72m$

$<b>Let the length an' breadth be denoted as x.</b>$

Then, the length = x + 4

Breadth = x

Perimeter = 2(l+b)

$72m$ = 2(x + x + 4)

$72m$ = 2(2x + 4)

$72m$ = 4x + 8

$72m - 8$ = 4x

$64m$ = 4x

$\frac{64}{4}$ = x

16 = x

$<b>Therefore, the value of x is 16.</b>$

Thus, the value of length = x + 4

The value of length = 16 + 4

$<b>The value of length = 20m</b>$

The value of breadth = x

$<b>The value of breadth = 16m</b>$

Thanks.....!

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