Question

Half the perimeter of a rectangular garden , whose lenght is 4m more than its width , is 36m . find the dimension of the garden.​

Answer 1

Answer:

Question:-

Half the perimeter of a garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.

Solution:-

Let the width = x

Length = x + 4

Perimeter = $2(l + b)$

⇒ $\frac{2(l + b)}{2} = 36$

$\frac{2(x + x + 4)}{2} = 36$

$\frac{2(2x + 4)}{2} = 36$

$4x + 8 = 36 * 2$

$4x + 8 = 72$

$4x = 72 - 8$

$4x = 64$

$x =\frac{64}{4}$

$x = 16$

$x + 4\\= 16 + 4\\= 20$

Breadth = 16 m

Length = 20 m

Verify:-

$2(l + b)$

$= 2(16 + 20)$

$= 2(36)$

Now if we assume that the total perimeter is ‘y’, we come up with the following equation:-

$2(36) = y$

$36 = \frac{y}{2}$

This proves that with the following dimensions, 36 will be half of the total perimeter, i.e. 72 m.

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Answer 2

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