Question

*Harpreet scored 10 marks more in the second test than that in the first. 5 times the score of the second test is the same as the square of the score in the first test. Find his score in the second test.*

1️⃣ 10
2️⃣ 20
3️⃣ 100
4️⃣ 50

Answer 1

Solution :

Let us assume that the marks scored by Harpreet in the first test is x .

So , in the second test he scored 10 more or ( x + 10) .

5 times the score of the second test is the same as the square of the score in the first test .

So ,

5( x + 10 ) = x²

=> x² - 5x - 50 = 0

=> x² - 10x + 5x - 50 = 0

=> x ( x - 10) + 5( x - 10 ) = 0

=> ( x + 5)( x - 10) = 0

• x = -5

• x = 10

x can't be negative , hence the value of -5 is discarded.

x = 10

x + 10 = 10 + 10 = 20 .

Hence , his score in the second test is 20.

Option (2) is the correct answer .

_______________________________

Answer 2

Answer:

Question:-

Harpreet scored 10 Mark's more in second test than in first test. 5 times the score of second test is the same as the square of the score in the first test .

Step- step- explanation

Given Conditions:-

• Harpreet scored 10 Mark's more in second test than in first
• 5 times the score of the second test is same as the square of the score in first test

Find out in the question:-

• Score of him in second test

Knowledge required:-

Let us assume that the marks scored by Harpreet in the first test is x.

So , in the second test he scored 10 more or ( x + 10) .

5 times the score of the second test is the same as the square of the score in the first test .

Let's find out step by step

So ,

5( x + 10 ) = x²

=> x² - 5x - 50 = 0

=> x² - 10x + 5x - 50 = 0

=> x ( x - 10) + 5( x - 10 ) = 0

=> ( x + 5)( x - 10) = 0

• x = -5

• x = 10

x can't be negative , hence the value of -5 is discarded.

x = 10

x + 10 = 10 + 10 = 20 .

Hence , his score in the second test is 20. Option (2) is the correct answer