*Harpreet scored 10 marks more in the second test than that in the first. 5 times the score of the second test is the same as the square of the score in the first test. Find his score in the second test.*
1️⃣ 10
2️⃣ 20
3️⃣ 100
4️⃣ 50
Answers
Solution :
Let us assume that the marks scored by Harpreet in the first test is x .
So , in the second test he scored 10 more or ( x + 10) .
5 times the score of the second test is the same as the square of the score in the first test .
So ,
5( x + 10 ) = x²
=> x² - 5x - 50 = 0
=> x² - 10x + 5x - 50 = 0
=> x ( x - 10) + 5( x - 10 ) = 0
=> ( x + 5)( x - 10) = 0
• x = -5
• x = 10
x can't be negative , hence the value of -5 is discarded.
x = 10
x + 10 = 10 + 10 = 20 .
Hence , his score in the second test is 20.
Option (2) is the correct answer .
_______________________________
Answer:
Question:-
Harpreet scored 10 Mark's more in second test than in first test. 5 times the score of second test is the same as the square of the score in the first test .
Step- step- explanation
Given Conditions:-
- Harpreet scored 10 Mark's more in second test than in first
- 5 times the score of the second test is same as the square of the score in first test
Find out in the question:-
- Score of him in second test
Knowledge required:-
Let us assume that the marks scored by Harpreet in the first test is x.
So , in the second test he scored 10 more or ( x + 10) .
5 times the score of the second test is the same as the square of the score in the first test .
Let's find out step by step
So ,
5( x + 10 ) = x²
=> x² - 5x - 50 = 0
=> x² - 10x + 5x - 50 = 0
=> x ( x - 10) + 5( x - 10 ) = 0
=> ( x + 5)( x - 10) = 0
• x = -5
• x = 10
x can't be negative , hence the value of -5 is discarded.
x = 10
x + 10 = 10 + 10 = 20 .
Hence , his score in the second test is 20. Option (2) is the correct answer