Question

hcf and lcm of five two digit numbers are 3 and 60060 resp. if one of the number is 12 then find other number

Answer 1

Let the two numbers be a & b
HCF = 3
LCM = 60060
a = 12

LCM×HCF = Product of two numbers
LCM×HCF = a×b

60060×3 = 12b
b = 15015
___________________________
hence the other number is 15015

Answer 2

15,33,39,21

Step-by-step explanation:

LCM = GCD × U.C ( product of uncommon factors)

So, 60060=3× U.C

=>U.C = 20020

Out of these uncommon factors 4 is already used to get the number 12 as the numbers are always the products of GCD and uncommon factor.

Therefore, remaining product = 20020÷4= 5005

Remaining numbers to be formed = 4

Therefore we have to split 5005 into 4 factors which are co prime to each other.

5005 = 5×1001

= 5×11×91

= 5×11×13×7

These factors are all co prime to each other

Thus, the numbers are 3×5=15, 3×11=33, 3×13=39, 3×7=21.

Hope this helps