Math, asked by Masoodrph14321, 11 months ago

Hcf and lcm of two numbers are 8 and 576, if one is 64, find the other

Answers

Answered by Anonymous
30

HEre Is Your Ans

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Let Required Number Be B

We Know That ,

 =  > hcf \: (a \:and \:  b) =  \frac{a \times b}{lcm(a \: and \: b)}  \\  \\  =  > 8 =   \frac{64  \times b}{576}  \\  \\  =  > b =  \frac{4608}{64}  \\  \\  =  > b = 72

Hence , Required Number Is  \fbox{72}

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Hope It Helps U

Answered by souravdas1430
3

Answer:

The answer is 72

Step-by-step explanation:

As we know that HCF×LCM = Product of the two numbers.

So 8×576= 64 × x ( let x be the other number)

=> x= (8× 576)/64

=> x= 72

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