HCF of 60,48 and 108
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Answered by
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Expressing as prime factors:
60 = 6*10 = 2*3*2*5 = 2^2 * 3 * 5
48 = 16*3 = 2^4 * 3
108 = 27*4 = 2^2 * 3^3
H.C.F(60,48,108) = 2^2 * 3 = 4*3 = 12
Hope it helps.
60 = 6*10 = 2*3*2*5 = 2^2 * 3 * 5
48 = 16*3 = 2^4 * 3
108 = 27*4 = 2^2 * 3^3
H.C.F(60,48,108) = 2^2 * 3 = 4*3 = 12
Hope it helps.
Answered by
6
Please mark this as a brainlist answer. hi
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