Question

If zeroes of the polynomial f(x)= ax^3-6x^2 +11x-6 is 4, find a

Answer 1

Hola there,

Given: p(x) = ax³ - 6x² + 11x - 6

and p(4) = 0

So,

=> (4)³a - 6(4)² + 11(4) - 6 = 0

=> 64a - 6×16 + 44 - 6 = 0

=> 64a - 96 + 44 - 6 = 0

=> 64a - 58 = 0

=> a = 58/64

=> a = 29/32

Hope this helps..:)

Answer 2

Hey mate !!!

here is your answer!!!

ax³ - 6 x² + 11 x - 6 = 0

zeroes is given ,. that is => 4

so on putting the value of zeroes in polynomial .

we get

a(4)³ - 6 (4)² +11 *4 -6 =0

=> 64a - 96 + 44 -6 =0

=> 64a -58 =0

a = 58 / 64 Answer





simplify it in simplest form

hope it helps you dear!!!

thanks