Question

Hcf of two number is 67 and there sum is 670 how many numbers are possible

Answer 1

those numbers will be multiple of 67.
let the no are " 67a and 67b" where a and b are positive integer.

sum = 670
=> 67(a+b)= 670
=> a + b = 10 --------(i)

here

there will be 9 pairs of (a,b) in which we will have only 5 different sets of required numbers.
again 5th pair will have two same no.

so, there will be 4 possible pairs of the no.


no. will be {(67,603),(134,536),(201,469),(268,402)}