Hcf of two numbers is 5 and their lcm is 210.if one of the numbers is30,then find the other number?
Answers
Answered by
16
HCF × LCM = a× b
5× 120 = 30 ×b
600÷30 = b
b= 20
5× 120 = 30 ×b
600÷30 = b
b= 20
Answered by
10
Hello friend!!!
Here's your answer
The product of hcf and lcm is equal to the product of the 2 number.
Mathematically, HCF × LCM = n1 × n2
◆But note that this formula is applicable for 2 number only◆
So from your question,
5 × 210 = 30 × n2
n2 = (5 × 210)/30 = 35
So the other number is 35.
HOPE THIS HELPS...... ☺️
Here's your answer
The product of hcf and lcm is equal to the product of the 2 number.
Mathematically, HCF × LCM = n1 × n2
◆But note that this formula is applicable for 2 number only◆
So from your question,
5 × 210 = 30 × n2
n2 = (5 × 210)/30 = 35
So the other number is 35.
HOPE THIS HELPS...... ☺️
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