Question

hcf of two numbers is 6 times less than their lcm if one number is 6 find other

Answer 1

Assuming other number is natural number.

Steps:
1 ) Let the HCF be 'x'.
According to question,
Then, the LCM becomes '6x'.
Let the other number be 'n'.

2) We know that,
Product of two Numbers =HCF * LCM of both
$= > 6 \times n = x \times 6x \\ = > 6n = 6 {x}^{2} \\ = > n = {x}^{2}$


Therefore, other number is square of HCF of two numbers .
If HCF is 1 , other number is 1 :
If HCF is 2, other number is 4:
This way Other number varies with HCF of given numbers.