HCF of two The numbers is 48, and the HCF of two other numbers is 36, Then the HCF of all four members is:
Answers
If a , b are two numbers and h , l are
their HCF and LCM then
h × l
Here ,
a = 36 , b = 48 ,
h = 12 , l = ?
h × l = a × b
l = ( a × b )/h
l = ( 36 × 48 )/12
l = 36 × 4
l = 144
Therefore ,
LCM ( 36 , 48 ) = 144
Answer:
12. (HCF of 48 and 36).
Step-by-step explanation:
HCF refers to the highest common Factor.
When taking HCF of more than 2 numbers,
For 3 numbers, the HCF of 3 numbers a,b,c is HCF(a,b,c) = HCF[hcf(a,b), c].
In this case, HCF of 2 numbers say 'a' and 'b' is 48 and another 2 numbers, say 'c' and 'd' which give a HCF of 36.
Lets take a = 48 and b = 96. which would satisfy this case.(Use any other numbers which are multiples of 48 to confirm). The HCF of these two is 48.
Lets take c = 36 and d =72 (multiples of 36).
HCF(a, b, c, d) = [HCF(a, b), HCF(c, d)] =HCF[48, 36] = 12.
Can also write HCF(a, b, c, d) = [HCF(a, b), HCF(c, d)] = [HCF(a, c), HCF(b, d)] = [HCF(a, d), HCF(b, c)]