he diameters of three concentric circles are in the ratio 1:2:3. the sum there circumference is 264 find the area enclosed between second and third circle.
Answers
Answered by
5
let d1/2:d2/2:d3/3= r1:r2:r3=1/2:2/2:3/2= 1:2:3
let,radius 1x,2x,3x respect.
2π.1x+2π.2x+2π.3x= 264(given)
so, X=7
So from that we find the radius of all circle and area between 2nd and 3rd circle
let,radius 1x,2x,3x respect.
2π.1x+2π.2x+2π.3x= 264(given)
so, X=7
So from that we find the radius of all circle and area between 2nd and 3rd circle
Answered by
0
Answer:
Step-by-step explanation:
d
1
=x,d
2
=2x,d
3
=3x
Sum of circumference =π(d
1
+d
2
+d
3
)
⇒264=π(6x)⇒x=14
A
2
=πr
2
2
=
4
π
d
2
2
=
4
π
×4x
2
=196cm
2
A
3
=
4
πd
3
2
=
4
π
×9x
2
=441πcm
2
Similar questions