Question

He difference between two numbers is 4 and the difference of their the difference between two numbers is 4 and the difference of their the difference between two numbers is 4 and the difference of their squares is 152. the sum of these two numbers is

Answer 1

Let the two numbers be x and y
X-y = 4
X^2 - y^2 = 152
X = 4 +y
(4+y) ^2 - y^2 = 152
16+y^2+8y-y^2 = 152
8y = 152 - 16
8y = 136
Y = 136/8
Y= 17.
X-y=4
X - 17 = 4
X = 21

The sum of the 2 numbers is 17+21 = 38

Answer 2

Answer:

let the numbers be x and y

according to the question,

x - y = 4 .........i

and,x² - y² = 152 ........ii

dividing equation ii with equation i

then

$\frac{ {x}^{2 } - {y}^{2} }{x - y} = \frac{152}{4} \\ = > \frac{(x + y)(x - y)}{x - y} = 38 \\ = > x + y = 38$

x + y = 38 ......iii

so the sum of the numbers is 38.

Step-by-step explanation:

on solving equation i and iii

we get ,

x = 21

and y = 17

so, the numbers are 21 and 17.