he intensity of sound from a point source is 1.0 x10⁻⁸ W/m² at a distance of 5.0 m from the source. What will be the intensity at a distance of 25 m from the source?
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Answer ⇒ Intensity at point 25 m away is 4 × 10⁻¹⁰ W/m².
Explanation ⇒ We know that the intensity is inversely proportional to the square of the distance from the source.
Thus,
I/I' = (d'/d)²
This means, Intensity I is at point d and Intensity I' is at point d'.
Thus, d = 5 m and d' = 25 m.
I = 10⁻⁸ W/m².
∴ 10⁻⁸/I' = (25/5)²
∴ 10⁻⁸/I' = 25
∴ I' = 4 × 10⁻¹⁰ W/m².
Hope it helps.
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