Question

He osmotic pressure of solution containing 34.2 g of cane sugar (molar mass = 342 g mol-1 ) in 1l of solution at 200 c is (given, r = 0.082 l atm k-1 mol-1)

Answer 1

Answer:

Explanation:

The osmotic pressure is equal to the product of concentration temperature and reidgber const

Osmostic pressure = C*R*T

Now given that molar mass 342g and

And gram molar mass is 34.2

Hence no. Of moles is given mass/gmm

342/34.2=10

Thus conc is moles per volume

Hence conc = 10/1= 10

And R = 0.0821

Temperature = 273+200= 473k

Thus osmostic pressure= 10*473*0.0821

Osmostic pressure= 388.3