He probability that a man fishing at a particular place will catch 1, 2, 3, 4 fishes are 0.4, 0.3, 0.2, 0.1 respectively. the expected number of fishes caught is
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As you know,
P(E) = n(E)/n(S)
Here P(E) is the probability of given events
n(E) is the events
n(S) is the same space .
For this explanation we can say that,
Number of fishes caught = P₁(E) × n₁(S) + P₂(E) × n₂(S) + P₃(E) × n₃(S) + P₄(E) × n₄(S)
Now put the values ,
Number of fishes caught = 1 × 0.4 + 2 × 0.3 + 3 × 0.2 + 0.1 × 4 = 0.4 + 0.6 + 0.6 + 0.4 = 2
Hence, answer is 2
P(E) = n(E)/n(S)
Here P(E) is the probability of given events
n(E) is the events
n(S) is the same space .
For this explanation we can say that,
Number of fishes caught = P₁(E) × n₁(S) + P₂(E) × n₂(S) + P₃(E) × n₃(S) + P₄(E) × n₄(S)
Now put the values ,
Number of fishes caught = 1 × 0.4 + 2 × 0.3 + 3 × 0.2 + 0.1 × 4 = 0.4 + 0.6 + 0.6 + 0.4 = 2
Hence, answer is 2
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