Question

heavy body is projected at an angle of 30 degree with horizontal find its velocity at the highest point if its velocity of projection is 10 metre per second​

Answer 1

Answer:5 root 3 m/s

Explanation:

When a projectile is at its highest point then its vertical component of velocity is 0 and what remains is its horizontal component of velocity i.e. u cos theta (here theta=30 degree and u=10m/s).

therefore, at highest point its velocity is 10*cos 30 = 10*(root3/2) = 5 root 3 m/s

Answer 2

Answer:

5√3

Explanation:

At the highest point velocity in Y direction will be 0.

So, Velocity At the highest point = Velocity in X direction

V = 10 cos30°

V = 10 * √3/2

V = 5√3