Helium gas is filled in 2 identical bottles A and B. The mass of the gas in the 2 bottles is 10gm and 40gm respectively. If the speed of sound is same in both bottles, what conclusion will you draw?
Answers
Answered by
11
Mass of helium in bottle A is 10g = M1
Mass of helium in bottle B is 40g=M2
Speed of sound in bottle A is equal to speed of sound in bottle B
V1 =V2
Therefore , root T1 / root M1 - root T2 / root M2
Therefore, T1 / M1 - T2 / M2
Therefore , T1 / 10 - T2 / 40 ( 4 T1 =T2 )
Temperature of bottle B is 4 times that of Bottle A.
Mass of helium in bottle B is 40g=M2
Speed of sound in bottle A is equal to speed of sound in bottle B
V1 =V2
Therefore , root T1 / root M1 - root T2 / root M2
Therefore, T1 / M1 - T2 / M2
Therefore , T1 / 10 - T2 / 40 ( 4 T1 =T2 )
Temperature of bottle B is 4 times that of Bottle A.
ShivPriya:
pls mark it as brainliest
If the option comes pls mark it as brainliest
Similar questions