Question

hello friends could you pls answer my qn​

Answer 1

Answer:

I don't &gggggggggggggggggggggggggggggggggggggggg

Answer 2

Answer:

Option(d)

Step-by-step explanation:

Given,

x = p sec∅

sec∅ = x/p   ------ (1)

and

y = q tan ∅

tan∅ = y/q     ----- (2)

On squaring (1) and (2), we get

sec²∅ = x²/p²

tan²∅ = y²/q²

We know,

sec²∅ - tan²∅ = 1

(x²/p²) - (y²/q²)  = 1

∴ x²q² - p²y² = p²q²

Hope it helps!