Question

Hello Guys, I need Help.
Please Any Expert Help me

The perimeter of a rhombus is 164 cm. If the length of one of the diagonals is 18 cm, find the length of other diagonal . Hence, find the area of the Rhombus.​

Answer 1

I think this helps u

plz.. mark it as brainlist answer....

Answer 2

Answer :

• Length of other Diagonal = 80 cm
• Area of Rhombus = 720 cm²

Step-by-step explanation:

Given :

• Perimeter of Rhombus = 164 cm

We know that ,

Perimeter of Rhombus = 4 × side

Let side be 'a' cm

•°• 4 × a = 164

$a = > = \frac{164}{4} = 41$

→Side of Rhombus is 41 cm

★Now we have in a right angle ∆

Hypotenuse = 41 cm

Base = ½ (18) = 9cm

Applying Pythagoras Theorem ,

(41)² = (9)² + (P)²

1681 = 81 + P²

P² = 1600

→ P = 40 cm

Diagonal = 40+40 = 80 cm

•°• The length of other Diagonal is 80 cm

°•°Area of Rhombus = ½ × ( product of diagonal )

= ½ × 18 × 80

= 40 × 18

= 720 cm²

●▬▬▬▬▬ஜ۩[THANKS]۩ஜ▬▬▬▬▬▬●